Turns+3+&+4

Wheel Diameter = 3.8cm Wheel Circumference = 3.8cm(3.14) = 11.932cm T-Circle-Diameter = 45cm T-Circle-Circumference=45cm(3.14) = 141.3cm 1. 72 Degree Turn: How far does the wheel need to travel? 0.2 = (distance/141.3cm)
 * __72 d__ || = || __dist__ ||  ||   ||   ||   ||   ||   ||
 * 360 d ||  || 141.3cm ||   ||   ||   ||   ||   ||   ||

0.2(141.3cm) = (distance/141.3cm)(141.3cm) 28.26cm = distance

2. How many rotations will roll the required distance? 28.26cm = (11.93cm)(Rotations) (28.26cm/11.93cm) = (11.93cm/11.93cm)(Rotations) 2.369 = Rotations

3. How many program degrees equals the required rotations? 852.8 program degrees
 * 2.369 Rotations x || __360 degrees__ ||  ||   ||   ||   ||   ||   ||   ||
 * || 1 Rotation ||  ||   ||   ||   ||   ||   ||   ||

Wheel Diameter = 6.8cm Wheel Circumference = 6.8cm(3.14) =21.35cm T-Circle Diameter = 38cm T-Circle Circumference = 38cm(3.14) = 119.32

1. To turn 32 degrees, what distance does the wheel need to go? First Method 0.08889 = (distance/119.32) (0.08889)(119.32) = (distance/119.32)(119.32) = distance Second method 32(119.32) = 360(distance) 3818.24/360 = (360/360)(distance) 10.606cm = distance 2. How many Rotations? 3. How many Program Degrees?
 * __32 degrees__ || = || __distance__ ||  ||   ||   ||   ||   ||   ||
 * 360 deg ||  || 119.32cm ||   ||   ||   ||   ||   ||   ||